It is assumed that it always does this when accelerated. Sometimes when a charge is accelerated (change speed or direction) it radiates energy. And anyway an object in circular motion gets the OTHER kind of radiation, that cancels out in the linear case. Still, you might get some special insight by looking at it some other way. It's a change in potential, and it doesn't get cancelled out by any of the other derivatives. ![]() That is, the radiation comes directly because of the acceleration at right angles, and all the complications when the acceleration is at other angles are to account for other things like compression of field lines etc which we also have to account for with everything else.Īcceleration just does that. It's the derivative of velocity with time, and it declines linearly with distance, and that's about it. If you look at the special case of linear acceleration, and the special case where the velocity (and acceleration) are at right angles to the direction of the target that's getting the force, one of the two electrical radiation terms cancels out and the other is very simple. These are two equations, one scalar and one vector (for the velocity) give all the electrical, magnetic, and radiative forces when you take the derivatives in space and time. I don't want to say you're wrong, but here's a different way you might try looking at it, which I'm sure is right.Īll of classical electromagnetism (between two particles, in vacuum) can be derived from the Lienard-Wiechert equations. So, imo, it will always, or at least for a long time, have a role to play in physics education. Experiment -> model -> new experiment -> new model, etc etc. At High schools, it's maybe a couple of lessons tops, so barely any time wasted on the "wrong" answer before you move on, and in the process you get some good discussion in about how Science even works.
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